Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=-133,-711
x=-\frac{13}{3} , -\frac{7}{11}
Mixed number form: x=-413,-711
x=-4\frac{1}{3} , -\frac{7}{11}
Decimal form: x=4.333,0.636
x=-4.333 , -0.636

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|7x+10|=|4x3|
without the absolute value bars:

|x|=|y||7x+10|=|4x3|
x=+y(7x+10)=(4x3)
x=y(7x+10)=(4x3)
+x=y(7x+10)=(4x3)
x=y(7x+10)=(4x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||7x+10|=|4x3|
x=+y , +x=y(7x+10)=(4x3)
x=y , x=y(7x+10)=(4x3)

2. Solve the two equations for x

9 additional steps

(7x+10)=(4x-3)

Subtract from both sides:

(7x+10)-4x=(4x-3)-4x

Group like terms:

(7x-4x)+10=(4x-3)-4x

Simplify the arithmetic:

3x+10=(4x-3)-4x

Group like terms:

3x+10=(4x-4x)-3

Simplify the arithmetic:

3x+10=3

Subtract from both sides:

(3x+10)-10=-3-10

Simplify the arithmetic:

3x=310

Simplify the arithmetic:

3x=13

Divide both sides by :

(3x)3=-133

Simplify the fraction:

x=-133

10 additional steps

(7x+10)=-(4x-3)

Expand the parentheses:

(7x+10)=-4x+3

Add to both sides:

(7x+10)+4x=(-4x+3)+4x

Group like terms:

(7x+4x)+10=(-4x+3)+4x

Simplify the arithmetic:

11x+10=(-4x+3)+4x

Group like terms:

11x+10=(-4x+4x)+3

Simplify the arithmetic:

11x+10=3

Subtract from both sides:

(11x+10)-10=3-10

Simplify the arithmetic:

11x=310

Simplify the arithmetic:

11x=7

Divide both sides by :

(11x)11=-711

Simplify the fraction:

x=-711

3. List the solutions

x=-133,-711
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|7x+10|
y=|4x3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.