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Solution - Absolute value equations

Exact form: x=0,0
x=0 , 0

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|73x|=|113x|
without the absolute value bars:

|x|=|y||73x|=|113x|
x=+y(73x)=(113x)
x=y(73x)=(113x)
+x=y(73x)=(113x)
x=y(73x)=(113x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||73x|=|113x|
x=+y , +x=y(73x)=(113x)
x=y , x=y(73x)=(113x)

2. Solve the two equations for x

3 additional steps

73x=113x

Subtract from both sides:

(73x)-113x=(113x)-113x

Simplify the arithmetic:

-40x=(113x)-113x

Simplify the arithmetic:

40x=0

Divide both sides by the coefficient:

x=0

11 additional steps

73x=113x

Divide both sides by :

(73x)73=(-113x)73

Simplify the fraction:

x=(-113x)73

Add to both sides:

x+11373·x=((-113x)73)+11373x

Group the coefficients:

(1+11373)x=((-113x)73)+11373x

Convert the integer into a fraction:

(7373+11373)x=((-113x)73)+11373x

Combine the fractions:

(73+113)73·x=((-113x)73)+11373x

Combine the numerators:

18673·x=((-113x)73)+11373x

Combine the fractions:

18673·x=(-113+113)73x

Combine the numerators:

18673·x=073x

Reduce the zero numerator:

18673x=0x

Simplify the arithmetic:

18673x=0

Divide both sides by the coefficient:

x=0

3. List the solutions

x=0,0
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|73x|
y=|113x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.