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Solution - Absolute value equations

Exact form: k=6
k=6

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|k+7|=|k+5|
without the absolute value bars:

|x|=|y||k+7|=|k+5|
x=+y(k+7)=(k+5)
x=y(k+7)=(k+5)
+x=y(k+7)=(k+5)
x=y(k+7)=(k+5)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||k+7|=|k+5|
x=+y , +x=y(k+7)=(k+5)
x=y , x=y(k+7)=(k+5)

2. Solve the two equations for k

5 additional steps

(-k+7)=(-k+5)

Add to both sides:

(-k+7)+k=(-k+5)+k

Group like terms:

(-k+k)+7=(-k+5)+k

Simplify the arithmetic:

7=(-k+5)+k

Group like terms:

7=(-k+k)+5

Simplify the arithmetic:

7=5

The statement is false:

7=5

The equation is false so it has no solution.

14 additional steps

(-k+7)=-(-k+5)

Expand the parentheses:

(-k+7)=k-5

Subtract from both sides:

(-k+7)-k=(k-5)-k

Group like terms:

(-k-k)+7=(k-5)-k

Simplify the arithmetic:

-2k+7=(k-5)-k

Group like terms:

-2k+7=(k-k)-5

Simplify the arithmetic:

2k+7=5

Subtract from both sides:

(-2k+7)-7=-5-7

Simplify the arithmetic:

2k=57

Simplify the arithmetic:

2k=12

Divide both sides by :

(-2k)-2=-12-2

Cancel out the negatives:

2k2=-12-2

Simplify the fraction:

k=-12-2

Cancel out the negatives:

k=122

Find the greatest common factor of the numerator and denominator:

k=(6·2)(1·2)

Factor out and cancel the greatest common factor:

k=6

3. Graph

Each line represents the function of one side of the equation:
y=|k+7|
y=|k+5|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.