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Solution - Absolute value equations

Exact form: a=76,7
a=\frac{7}{6} , 7
Mixed number form: a=116,7
a=1\frac{1}{6} , 7
Decimal form: a=1.167,7
a=1.167 , 7

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|6a+7|=|6a7|
without the absolute value bars:

|x|=|y||6a+7|=|6a7|
x=+y(6a+7)=(6a7)
x=y(6a+7)=(6a7)
+x=y(6a+7)=(6a7)
x=y(6a+7)=(6a7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||6a+7|=|6a7|
x=+y , +x=y(6a+7)=(6a7)
x=y , x=y(6a+7)=(6a7)

2. Solve the two equations for a

13 additional steps

(-6a+7)=(6a-7)

Subtract from both sides:

(-6a+7)-6a=(6a-7)-6a

Group like terms:

(-6a-6a)+7=(6a-7)-6a

Simplify the arithmetic:

-12a+7=(6a-7)-6a

Group like terms:

-12a+7=(6a-6a)-7

Simplify the arithmetic:

12a+7=7

Subtract from both sides:

(-12a+7)-7=-7-7

Simplify the arithmetic:

12a=77

Simplify the arithmetic:

12a=14

Divide both sides by :

(-12a)-12=-14-12

Cancel out the negatives:

12a12=-14-12

Simplify the fraction:

a=-14-12

Cancel out the negatives:

a=1412

Find the greatest common factor of the numerator and denominator:

a=(7·2)(6·2)

Factor out and cancel the greatest common factor:

a=76

5 additional steps

(-6a+7)=-(6a-7)

Expand the parentheses:

(-6a+7)=-6a+7

Add to both sides:

(-6a+7)+6a=(-6a+7)+6a

Group like terms:

(-6a+6a)+7=(-6a+7)+6a

Simplify the arithmetic:

7=(-6a+7)+6a

Group like terms:

7=(-6a+6a)+7

Simplify the arithmetic:

7=7

3. List the solutions

a=76,7
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|6a+7|
y=|6a7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.