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Solution - Absolute value equations

Exact form:

y = - 1, \frac{1}{5}

y=-1 , \frac{1}{5}

Decimal form:

y = - 1, 0.2

y=-1 , 0.2

See steps

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| 6 y | = 2 | 2 y - 1 |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| 6 y \| = 2 \| 2 y - 1 \|$
$x = + y$	$(6 y) = 2 (2 y - 1)$
$x = - y$	$(6 y) = 2 (- (2 y - 1))$
$+ x = y$	$(6 y) = 2 (2 y - 1)$
$- x = y$	$- (6 y) = 2 (2 y - 1)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| 6 y \| = 2 \| 2 y - 1 \|$
$x = + y$ , $+ x = y$	$(6 y) = 2 (2 y - 1)$
$x = - y$ , $- x = y$	$(6 y) = 2 (- (2 y - 1))$

2. Solve the two equations for y

9 additional steps

$6 y = 2 \cdot (2 y - 1)$

Expand the parentheses:

$6 y = 2 \cdot 2 y + 2 \cdot - 1$

Multiply the coefficients:

$6 y = 4 y + 2 \cdot - 1$

Simplify the arithmetic:

$6 y = 4 y - 2$

Subtract from both sides:

$(6 y) - 4 y = (4 y - 2) - 4 y$

Simplify the arithmetic:

$2 y = (4 y - 2) - 4 y$

Group like terms:

$2 y = (4 y - 4 y) - 2$

Simplify the arithmetic:

$2 y = - 2$

Divide both sides by :

$\frac{(2 y)}{2} = \frac{- 2}{2}$

Simplify the fraction:

$y = \frac{- 2}{2}$

Simplify the fraction:

$y = - 1$

11 additional steps

$6 y = 2 \cdot (- (2 y - 1))$

Expand the parentheses:

$6 y = 2 \cdot (- 2 y + 1)$

Expand the parentheses:

$6 y = 2 \cdot - 2 y + 2 \cdot 1$

Multiply the coefficients:

$6 y = - 4 y + 2 \cdot 1$

Simplify the arithmetic:

$6 y = - 4 y + 2$

Add to both sides:

$(6 y) + 4 y = (- 4 y + 2) + 4 y$

Simplify the arithmetic:

$10 y = (- 4 y + 2) + 4 y$

Group like terms:

$10 y = (- 4 y + 4 y) + 2$

Simplify the arithmetic:

$10 y = 2$

Divide both sides by :

$\frac{(10 y)}{10} = \frac{2}{10}$

Simplify the fraction:

$y = \frac{2}{10}$

Find the greatest common factor of the numerator and denominator:

$y = \frac{(1 \cdot 2)}{(5 \cdot 2)}$

Factor out and cancel the greatest common factor:

$y = \frac{1}{5}$

3. List the solutions

$y = - 1, \frac{1}{5}$
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
$y = | 6 y |$
$y = 2 | 2 y - 1 |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for y

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for y

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

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