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Solution - Absolute value equations

Exact form: x=-174,-116
x=-\frac{17}{4} , -\frac{1}{16}
Mixed number form: x=-414,-116
x=-4\frac{1}{4} , -\frac{1}{16}
Decimal form: x=4.25,0.062
x=-4.25 , -0.062

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|6x8|=|10x+9|
without the absolute value bars:

|x|=|y||6x8|=|10x+9|
x=+y(6x8)=(10x+9)
x=y(6x8)=(10x+9)
+x=y(6x8)=(10x+9)
x=y(6x8)=(10x+9)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||6x8|=|10x+9|
x=+y , +x=y(6x8)=(10x+9)
x=y , x=y(6x8)=(10x+9)

2. Solve the two equations for x

11 additional steps

(6x-8)=(10x+9)

Subtract from both sides:

(6x-8)-10x=(10x+9)-10x

Group like terms:

(6x-10x)-8=(10x+9)-10x

Simplify the arithmetic:

-4x-8=(10x+9)-10x

Group like terms:

-4x-8=(10x-10x)+9

Simplify the arithmetic:

4x8=9

Add to both sides:

(-4x-8)+8=9+8

Simplify the arithmetic:

4x=9+8

Simplify the arithmetic:

4x=17

Divide both sides by :

(-4x)-4=17-4

Cancel out the negatives:

4x4=17-4

Simplify the fraction:

x=17-4

Move the negative sign from the denominator to the numerator:

x=-174

10 additional steps

(6x-8)=-(10x+9)

Expand the parentheses:

(6x-8)=-10x-9

Add to both sides:

(6x-8)+10x=(-10x-9)+10x

Group like terms:

(6x+10x)-8=(-10x-9)+10x

Simplify the arithmetic:

16x-8=(-10x-9)+10x

Group like terms:

16x-8=(-10x+10x)-9

Simplify the arithmetic:

16x8=9

Add to both sides:

(16x-8)+8=-9+8

Simplify the arithmetic:

16x=9+8

Simplify the arithmetic:

16x=1

Divide both sides by :

(16x)16=-116

Simplify the fraction:

x=-116

3. List the solutions

x=-174,-116
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|6x8|
y=|10x+9|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.