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Solution - Absolute value equations

Exact form: x=-85,865
x=-\frac{8}{5} , \frac{8}{65}
Mixed number form: x=-135,865
x=-1\frac{3}{5} , \frac{8}{65}
Decimal form: x=1.6,0.123
x=-1.6 , 0.123

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|6x-85|=|7x|
without the absolute value bars:

|x|=|y||6x-85|=|7x|
x=+y(6x-85)=(7x)
x=-y(6x-85)=-(7x)
+x=y(6x-85)=(7x)
-x=y-(6x-85)=(7x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||6x-85|=|7x|
x=+y , +x=y(6x-85)=(7x)
x=-y , -x=y(6x-85)=-(7x)

2. Solve the two equations for x

12 additional steps

(6x+-85)=7x

Subtract from both sides:

(6x+-85)-7x=(7x)-7x

Group like terms:

(6x-7x)+-85=(7x)-7x

Simplify the arithmetic:

-x+-85=(7x)-7x

Simplify the arithmetic:

-x+-85=0

Add to both sides:

(-x+-85)+85=0+85

Combine the fractions:

-x+(-8+8)5=0+85

Combine the numerators:

-x+05=0+85

Reduce the zero numerator:

-x+0=0+85

Simplify the arithmetic:

-x=0+85

Simplify the arithmetic:

-x=85

Multiply both sides by :

-x·-1=(85)·-1

Remove the one(s):

x=(85)·-1

Remove the one(s):

x=-85

12 additional steps

(6x+-85)=-7x

Add to both sides:

(6x+-85)+85=(-7x)+85

Combine the fractions:

6x+(-8+8)5=(-7x)+85

Combine the numerators:

6x+05=(-7x)+85

Reduce the zero numerator:

6x+0=(-7x)+85

Simplify the arithmetic:

6x=(-7x)+85

Add to both sides:

(6x)+7x=((-7x)+85)+7x

Simplify the arithmetic:

13x=((-7x)+85)+7x

Group like terms:

13x=(-7x+7x)+85

Simplify the arithmetic:

13x=85

Divide both sides by :

(13x)13=(85)13

Simplify the fraction:

x=(85)13

Simplify the arithmetic:

x=8(5·13)

x=865

3. List the solutions

x=-85,865
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|6x-85|
y=|7x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.