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Solution - Absolute value equations

Exact form: x=13,-311
x=13 , -\frac{3}{11}
Decimal form: x=13,0.273
x=13 , -0.273

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|6x5|=|5x+8|
without the absolute value bars:

|x|=|y||6x5|=|5x+8|
x=+y(6x5)=(5x+8)
x=y(6x5)=(5x+8)
+x=y(6x5)=(5x+8)
x=y(6x5)=(5x+8)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||6x5|=|5x+8|
x=+y , +x=y(6x5)=(5x+8)
x=y , x=y(6x5)=(5x+8)

2. Solve the two equations for x

7 additional steps

(6x-5)=(5x+8)

Subtract from both sides:

(6x-5)-5x=(5x+8)-5x

Group like terms:

(6x-5x)-5=(5x+8)-5x

Simplify the arithmetic:

x-5=(5x+8)-5x

Group like terms:

x-5=(5x-5x)+8

Simplify the arithmetic:

x5=8

Add to both sides:

(x-5)+5=8+5

Simplify the arithmetic:

x=8+5

Simplify the arithmetic:

x=13

10 additional steps

(6x-5)=-(5x+8)

Expand the parentheses:

(6x-5)=-5x-8

Add to both sides:

(6x-5)+5x=(-5x-8)+5x

Group like terms:

(6x+5x)-5=(-5x-8)+5x

Simplify the arithmetic:

11x-5=(-5x-8)+5x

Group like terms:

11x-5=(-5x+5x)-8

Simplify the arithmetic:

11x5=8

Add to both sides:

(11x-5)+5=-8+5

Simplify the arithmetic:

11x=8+5

Simplify the arithmetic:

11x=3

Divide both sides by :

(11x)11=-311

Simplify the fraction:

x=-311

3. List the solutions

x=13,-311
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|6x5|
y=|5x+8|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.