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Solution - Absolute value equations

Exact form: x=2,14
x=2 , \frac{1}{4}
Decimal form: x=2,0.25
x=2 , 0.25

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|6x5|=|2x+3|
without the absolute value bars:

|x|=|y||6x5|=|2x+3|
x=+y(6x5)=(2x+3)
x=y(6x5)=(2x+3)
+x=y(6x5)=(2x+3)
x=y(6x5)=(2x+3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||6x5|=|2x+3|
x=+y , +x=y(6x5)=(2x+3)
x=y , x=y(6x5)=(2x+3)

2. Solve the two equations for x

11 additional steps

(6x-5)=(2x+3)

Subtract from both sides:

(6x-5)-2x=(2x+3)-2x

Group like terms:

(6x-2x)-5=(2x+3)-2x

Simplify the arithmetic:

4x-5=(2x+3)-2x

Group like terms:

4x-5=(2x-2x)+3

Simplify the arithmetic:

4x5=3

Add to both sides:

(4x-5)+5=3+5

Simplify the arithmetic:

4x=3+5

Simplify the arithmetic:

4x=8

Divide both sides by :

(4x)4=84

Simplify the fraction:

x=84

Find the greatest common factor of the numerator and denominator:

x=(2·4)(1·4)

Factor out and cancel the greatest common factor:

x=2

12 additional steps

(6x-5)=-(2x+3)

Expand the parentheses:

(6x-5)=-2x-3

Add to both sides:

(6x-5)+2x=(-2x-3)+2x

Group like terms:

(6x+2x)-5=(-2x-3)+2x

Simplify the arithmetic:

8x-5=(-2x-3)+2x

Group like terms:

8x-5=(-2x+2x)-3

Simplify the arithmetic:

8x5=3

Add to both sides:

(8x-5)+5=-3+5

Simplify the arithmetic:

8x=3+5

Simplify the arithmetic:

8x=2

Divide both sides by :

(8x)8=28

Simplify the fraction:

x=28

Find the greatest common factor of the numerator and denominator:

x=(1·2)(4·2)

Factor out and cancel the greatest common factor:

x=14

3. List the solutions

x=2,14
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|6x5|
y=|2x+3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.