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Solution - Absolute value equations

Exact form: x=-143,815
x=-\frac{14}{3} , \frac{8}{15}
Mixed number form: x=-423,815
x=-4\frac{2}{3} , \frac{8}{15}
Decimal form: x=4.667,0.533
x=-4.667 , 0.533

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|6x11|=|9x+3|
without the absolute value bars:

|x|=|y||6x11|=|9x+3|
x=+y(6x11)=(9x+3)
x=y(6x11)=(9x+3)
+x=y(6x11)=(9x+3)
x=y(6x11)=(9x+3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||6x11|=|9x+3|
x=+y , +x=y(6x11)=(9x+3)
x=y , x=y(6x11)=(9x+3)

2. Solve the two equations for x

11 additional steps

(6x-11)=(9x+3)

Subtract from both sides:

(6x-11)-9x=(9x+3)-9x

Group like terms:

(6x-9x)-11=(9x+3)-9x

Simplify the arithmetic:

-3x-11=(9x+3)-9x

Group like terms:

-3x-11=(9x-9x)+3

Simplify the arithmetic:

3x11=3

Add to both sides:

(-3x-11)+11=3+11

Simplify the arithmetic:

3x=3+11

Simplify the arithmetic:

3x=14

Divide both sides by :

(-3x)-3=14-3

Cancel out the negatives:

3x3=14-3

Simplify the fraction:

x=14-3

Move the negative sign from the denominator to the numerator:

x=-143

10 additional steps

(6x-11)=-(9x+3)

Expand the parentheses:

(6x-11)=-9x-3

Add to both sides:

(6x-11)+9x=(-9x-3)+9x

Group like terms:

(6x+9x)-11=(-9x-3)+9x

Simplify the arithmetic:

15x-11=(-9x-3)+9x

Group like terms:

15x-11=(-9x+9x)-3

Simplify the arithmetic:

15x11=3

Add to both sides:

(15x-11)+11=-3+11

Simplify the arithmetic:

15x=3+11

Simplify the arithmetic:

15x=8

Divide both sides by :

(15x)15=815

Simplify the fraction:

x=815

3. List the solutions

x=-143,815
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|6x11|
y=|9x+3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.