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Solution - Absolute value equations

Exact form: x=-5,57
x=-5 , \frac{5}{7}
Decimal form: x=5,0.714
x=-5 , 0.714

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|6x10|=|8x|
without the absolute value bars:

|x|=|y||6x10|=|8x|
x=+y(6x10)=(8x)
x=y(6x10)=(8x)
+x=y(6x10)=(8x)
x=y(6x10)=(8x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||6x10|=|8x|
x=+y , +x=y(6x10)=(8x)
x=y , x=y(6x10)=(8x)

2. Solve the two equations for x

12 additional steps

(6x-10)=8x

Subtract from both sides:

(6x-10)-8x=(8x)-8x

Group like terms:

(6x-8x)-10=(8x)-8x

Simplify the arithmetic:

-2x-10=(8x)-8x

Simplify the arithmetic:

2x10=0

Add to both sides:

(-2x-10)+10=0+10

Simplify the arithmetic:

2x=0+10

Simplify the arithmetic:

2x=10

Divide both sides by :

(-2x)-2=10-2

Cancel out the negatives:

2x2=10-2

Simplify the fraction:

x=10-2

Move the negative sign from the denominator to the numerator:

x=-102

Find the greatest common factor of the numerator and denominator:

x=(-5·2)(1·2)

Factor out and cancel the greatest common factor:

x=5

9 additional steps

(6x-10)=-8x

Add to both sides:

(6x-10)+10=(-8x)+10

Simplify the arithmetic:

6x=(-8x)+10

Add to both sides:

(6x)+8x=((-8x)+10)+8x

Simplify the arithmetic:

14x=((-8x)+10)+8x

Group like terms:

14x=(-8x+8x)+10

Simplify the arithmetic:

14x=10

Divide both sides by :

(14x)14=1014

Simplify the fraction:

x=1014

Find the greatest common factor of the numerator and denominator:

x=(5·2)(7·2)

Factor out and cancel the greatest common factor:

x=57

3. List the solutions

x=-5,57
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|6x10|
y=|8x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.