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Solution - Absolute value equations

Exact form:

x = 0, 0

x=0 , 0

See steps

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| 6 x | = - | 2 x |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| 6 x \| = - \| 2 x \|$
$x = + y$	$(6 x) = - (2 x)$
$x = - y$	$(6 x) = - (- (2 x))$
$+ x = y$	$(6 x) = - (2 x)$
$- x = y$	$- (6 x) = - (2 x)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| 6 x \| = - \| 2 x \|$
$x = + y$ , $+ x = y$	$(6 x) = - (2 x)$
$x = - y$ , $- x = y$	$(6 x) = - (- (2 x))$

2. Solve the two equations for x

12 additional steps

$6 x = - 2 x$

Divide both sides by :

$\frac{(6 x)}{6} = \frac{(- 2 x)}{6}$

Simplify the fraction:

$x = \frac{(- 2 x)}{6}$

Simplify the fraction:

$x = \frac{- 1}{3} x$

Add to both sides:

$x + \frac{1}{3} \cdot x = (\frac{- 1}{3} x) + \frac{1}{3} x$

Group the coefficients:

$(1 + \frac{1}{3}) x = (\frac{- 1}{3} \cdot x) + \frac{1}{3} x$

Convert the integer into a fraction:

$(\frac{3}{3} + \frac{1}{3}) x = (\frac{- 1}{3} \cdot x) + \frac{1}{3} x$

Combine the fractions:

$\frac{(3 + 1)}{3} \cdot x = (\frac{- 1}{3} \cdot x) + \frac{1}{3} x$

Combine the numerators:

$\frac{4}{3} \cdot x = (\frac{- 1}{3} \cdot x) + \frac{1}{3} x$

Combine the fractions:

$\frac{4}{3} \cdot x = \frac{(- 1 + 1)}{3} x$

Combine the numerators:

$\frac{4}{3} \cdot x = \frac{0}{3} x$

Reduce the zero numerator:

$\frac{4}{3} x = 0 x$

Simplify the arithmetic:

$\frac{4}{3} x = 0$

Divide both sides by the coefficient:

$x = 0$

5 additional steps

$6 x = - - 2 x$

Group like terms:

$6 x = (- 1 \cdot - 2) x$

Multiply the coefficients:

$6 x = 2 x$

Subtract from both sides:

$(6 x) - 2 x = (2 x) - 2 x$

Simplify the arithmetic:

$4 x = (2 x) - 2 x$

Simplify the arithmetic:

$4 x = 0$

Divide both sides by the coefficient:

$x = 0$

3. List the solutions

$x = 0, 0$
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
$y = | 6 x |$
$y = - | 2 x |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for x

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for x

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

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