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Solution - Absolute value equations

Exact form: x=2,-12
x=2 , -\frac{1}{2}
Decimal form: x=2,0.5
x=2 , -0.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|6x+8|=|10x|
without the absolute value bars:

|x|=|y||6x+8|=|10x|
x=+y(6x+8)=(10x)
x=y(6x+8)=(10x)
+x=y(6x+8)=(10x)
x=y(6x+8)=(10x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||6x+8|=|10x|
x=+y , +x=y(6x+8)=(10x)
x=y , x=y(6x+8)=(10x)

2. Solve the two equations for x

12 additional steps

(6x+8)=10x

Subtract from both sides:

(6x+8)-10x=(10x)-10x

Group like terms:

(6x-10x)+8=(10x)-10x

Simplify the arithmetic:

-4x+8=(10x)-10x

Simplify the arithmetic:

4x+8=0

Subtract from both sides:

(-4x+8)-8=0-8

Simplify the arithmetic:

4x=08

Simplify the arithmetic:

4x=8

Divide both sides by :

(-4x)-4=-8-4

Cancel out the negatives:

4x4=-8-4

Simplify the fraction:

x=-8-4

Cancel out the negatives:

x=84

Find the greatest common factor of the numerator and denominator:

x=(2·4)(1·4)

Factor out and cancel the greatest common factor:

x=2

9 additional steps

(6x+8)=-10x

Subtract from both sides:

(6x+8)-8=(-10x)-8

Simplify the arithmetic:

6x=(-10x)-8

Add to both sides:

(6x)+10x=((-10x)-8)+10x

Simplify the arithmetic:

16x=((-10x)-8)+10x

Group like terms:

16x=(-10x+10x)-8

Simplify the arithmetic:

16x=8

Divide both sides by :

(16x)16=-816

Simplify the fraction:

x=-816

Find the greatest common factor of the numerator and denominator:

x=(-1·8)(2·8)

Factor out and cancel the greatest common factor:

x=-12

3. List the solutions

x=2,-12
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|6x+8|
y=|10x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.