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Solution - Absolute value equations

Exact form: x=49,5
x=49 , -5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|6x+3|=|5x+52|
without the absolute value bars:

|x|=|y||6x+3|=|5x+52|
x=+y(6x+3)=(5x+52)
x=y(6x+3)=(5x+52)
+x=y(6x+3)=(5x+52)
x=y(6x+3)=(5x+52)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||6x+3|=|5x+52|
x=+y , +x=y(6x+3)=(5x+52)
x=y , x=y(6x+3)=(5x+52)

2. Solve the two equations for x

7 additional steps

(6x+3)=(5x+52)

Subtract from both sides:

(6x+3)-5x=(5x+52)-5x

Group like terms:

(6x-5x)+3=(5x+52)-5x

Simplify the arithmetic:

x+3=(5x+52)-5x

Group like terms:

x+3=(5x-5x)+52

Simplify the arithmetic:

x+3=52

Subtract from both sides:

(x+3)-3=52-3

Simplify the arithmetic:

x=523

Simplify the arithmetic:

x=49

12 additional steps

(6x+3)=-(5x+52)

Expand the parentheses:

(6x+3)=-5x-52

Add to both sides:

(6x+3)+5x=(-5x-52)+5x

Group like terms:

(6x+5x)+3=(-5x-52)+5x

Simplify the arithmetic:

11x+3=(-5x-52)+5x

Group like terms:

11x+3=(-5x+5x)-52

Simplify the arithmetic:

11x+3=52

Subtract from both sides:

(11x+3)-3=-52-3

Simplify the arithmetic:

11x=523

Simplify the arithmetic:

11x=55

Divide both sides by :

(11x)11=-5511

Simplify the fraction:

x=-5511

Find the greatest common factor of the numerator and denominator:

x=(-5·11)(1·11)

Factor out and cancel the greatest common factor:

x=5

3. List the solutions

x=49,5
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|6x+3|
y=|5x+52|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.