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Solution - Absolute value equations

Exact form: x=3,3
x=3 , -3

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|6x+3|=|x+18|
without the absolute value bars:

|x|=|y||6x+3|=|x+18|
x=+y(6x+3)=(x+18)
x=y(6x+3)=(x+18)
+x=y(6x+3)=(x+18)
x=y(6x+3)=(x+18)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||6x+3|=|x+18|
x=+y , +x=y(6x+3)=(x+18)
x=y , x=y(6x+3)=(x+18)

2. Solve the two equations for x

11 additional steps

(6x+3)=(x+18)

Subtract from both sides:

(6x+3)-x=(x+18)-x

Group like terms:

(6x-x)+3=(x+18)-x

Simplify the arithmetic:

5x+3=(x+18)-x

Group like terms:

5x+3=(x-x)+18

Simplify the arithmetic:

5x+3=18

Subtract from both sides:

(5x+3)-3=18-3

Simplify the arithmetic:

5x=183

Simplify the arithmetic:

5x=15

Divide both sides by :

(5x)5=155

Simplify the fraction:

x=155

Find the greatest common factor of the numerator and denominator:

x=(3·5)(1·5)

Factor out and cancel the greatest common factor:

x=3

12 additional steps

(6x+3)=-(x+18)

Expand the parentheses:

(6x+3)=-x-18

Add to both sides:

(6x+3)+x=(-x-18)+x

Group like terms:

(6x+x)+3=(-x-18)+x

Simplify the arithmetic:

7x+3=(-x-18)+x

Group like terms:

7x+3=(-x+x)-18

Simplify the arithmetic:

7x+3=18

Subtract from both sides:

(7x+3)-3=-18-3

Simplify the arithmetic:

7x=183

Simplify the arithmetic:

7x=21

Divide both sides by :

(7x)7=-217

Simplify the fraction:

x=-217

Find the greatest common factor of the numerator and denominator:

x=(-3·7)(1·7)

Factor out and cancel the greatest common factor:

x=3

3. List the solutions

x=3,3
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|6x+3|
y=|x+18|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.