Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=95,-157
x=\frac{9}{5} , -\frac{15}{7}
Mixed number form: x=145,-217
x=1\frac{4}{5} , -2\frac{1}{7}
Decimal form: x=1.8,2.143
x=1.8 , -2.143

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|6x+3|=|x+12|
without the absolute value bars:

|x|=|y||6x+3|=|x+12|
x=+y(6x+3)=(x+12)
x=y(6x+3)=(x+12)
+x=y(6x+3)=(x+12)
x=y(6x+3)=(x+12)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||6x+3|=|x+12|
x=+y , +x=y(6x+3)=(x+12)
x=y , x=y(6x+3)=(x+12)

2. Solve the two equations for x

9 additional steps

(6x+3)=(x+12)

Subtract from both sides:

(6x+3)-x=(x+12)-x

Group like terms:

(6x-x)+3=(x+12)-x

Simplify the arithmetic:

5x+3=(x+12)-x

Group like terms:

5x+3=(x-x)+12

Simplify the arithmetic:

5x+3=12

Subtract from both sides:

(5x+3)-3=12-3

Simplify the arithmetic:

5x=123

Simplify the arithmetic:

5x=9

Divide both sides by :

(5x)5=95

Simplify the fraction:

x=95

10 additional steps

(6x+3)=-(x+12)

Expand the parentheses:

(6x+3)=-x-12

Add to both sides:

(6x+3)+x=(-x-12)+x

Group like terms:

(6x+x)+3=(-x-12)+x

Simplify the arithmetic:

7x+3=(-x-12)+x

Group like terms:

7x+3=(-x+x)-12

Simplify the arithmetic:

7x+3=12

Subtract from both sides:

(7x+3)-3=-12-3

Simplify the arithmetic:

7x=123

Simplify the arithmetic:

7x=15

Divide both sides by :

(7x)7=-157

Simplify the fraction:

x=-157

3. List the solutions

x=95,-157
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|6x+3|
y=|x+12|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.