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Solution - Absolute value equations

Exact form: x=-52,110
x=-\frac{5}{2} , \frac{1}{10}
Mixed number form: x=-212,110
x=-2\frac{1}{2} , \frac{1}{10}
Decimal form: x=2.5,0.1
x=-2.5 , 0.1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|6x+2|=|4x3|
without the absolute value bars:

|x|=|y||6x+2|=|4x3|
x=+y(6x+2)=(4x3)
x=y(6x+2)=(4x3)
+x=y(6x+2)=(4x3)
x=y(6x+2)=(4x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||6x+2|=|4x3|
x=+y , +x=y(6x+2)=(4x3)
x=y , x=y(6x+2)=(4x3)

2. Solve the two equations for x

9 additional steps

(6x+2)=(4x-3)

Subtract from both sides:

(6x+2)-4x=(4x-3)-4x

Group like terms:

(6x-4x)+2=(4x-3)-4x

Simplify the arithmetic:

2x+2=(4x-3)-4x

Group like terms:

2x+2=(4x-4x)-3

Simplify the arithmetic:

2x+2=3

Subtract from both sides:

(2x+2)-2=-3-2

Simplify the arithmetic:

2x=32

Simplify the arithmetic:

2x=5

Divide both sides by :

(2x)2=-52

Simplify the fraction:

x=-52

10 additional steps

(6x+2)=-(4x-3)

Expand the parentheses:

(6x+2)=-4x+3

Add to both sides:

(6x+2)+4x=(-4x+3)+4x

Group like terms:

(6x+4x)+2=(-4x+3)+4x

Simplify the arithmetic:

10x+2=(-4x+3)+4x

Group like terms:

10x+2=(-4x+4x)+3

Simplify the arithmetic:

10x+2=3

Subtract from both sides:

(10x+2)-2=3-2

Simplify the arithmetic:

10x=32

Simplify the arithmetic:

10x=1

Divide both sides by :

(10x)10=110

Simplify the fraction:

x=110

3. List the solutions

x=-52,110
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|6x+2|
y=|4x3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.