Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=-2,12
x=-2 , \frac{1}{2}
Decimal form: x=2,0.5
x=-2 , 0.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|6x+2|=|2x6|
without the absolute value bars:

|x|=|y||6x+2|=|2x6|
x=+y(6x+2)=(2x6)
x=y(6x+2)=(2x6)
+x=y(6x+2)=(2x6)
x=y(6x+2)=(2x6)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||6x+2|=|2x6|
x=+y , +x=y(6x+2)=(2x6)
x=y , x=y(6x+2)=(2x6)

2. Solve the two equations for x

11 additional steps

(6x+2)=(2x-6)

Subtract from both sides:

(6x+2)-2x=(2x-6)-2x

Group like terms:

(6x-2x)+2=(2x-6)-2x

Simplify the arithmetic:

4x+2=(2x-6)-2x

Group like terms:

4x+2=(2x-2x)-6

Simplify the arithmetic:

4x+2=6

Subtract from both sides:

(4x+2)-2=-6-2

Simplify the arithmetic:

4x=62

Simplify the arithmetic:

4x=8

Divide both sides by :

(4x)4=-84

Simplify the fraction:

x=-84

Find the greatest common factor of the numerator and denominator:

x=(-2·4)(1·4)

Factor out and cancel the greatest common factor:

x=2

12 additional steps

(6x+2)=-(2x-6)

Expand the parentheses:

(6x+2)=-2x+6

Add to both sides:

(6x+2)+2x=(-2x+6)+2x

Group like terms:

(6x+2x)+2=(-2x+6)+2x

Simplify the arithmetic:

8x+2=(-2x+6)+2x

Group like terms:

8x+2=(-2x+2x)+6

Simplify the arithmetic:

8x+2=6

Subtract from both sides:

(8x+2)-2=6-2

Simplify the arithmetic:

8x=62

Simplify the arithmetic:

8x=4

Divide both sides by :

(8x)8=48

Simplify the fraction:

x=48

Find the greatest common factor of the numerator and denominator:

x=(1·4)(2·4)

Factor out and cancel the greatest common factor:

x=12

3. List the solutions

x=-2,12
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|6x+2|
y=|2x6|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.