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Solution - Absolute value equations

Exact form: x=-132,-710
x=-\frac{13}{2} , -\frac{7}{10}
Mixed number form: x=-612,-710
x=-6\frac{1}{2} , -\frac{7}{10}
Decimal form: x=6.5,0.7
x=-6.5 , -0.7

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|6x+10|=|4x3|
without the absolute value bars:

|x|=|y||6x+10|=|4x3|
x=+y(6x+10)=(4x3)
x=y(6x+10)=(4x3)
+x=y(6x+10)=(4x3)
x=y(6x+10)=(4x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||6x+10|=|4x3|
x=+y , +x=y(6x+10)=(4x3)
x=y , x=y(6x+10)=(4x3)

2. Solve the two equations for x

9 additional steps

(6x+10)=(4x-3)

Subtract from both sides:

(6x+10)-4x=(4x-3)-4x

Group like terms:

(6x-4x)+10=(4x-3)-4x

Simplify the arithmetic:

2x+10=(4x-3)-4x

Group like terms:

2x+10=(4x-4x)-3

Simplify the arithmetic:

2x+10=3

Subtract from both sides:

(2x+10)-10=-3-10

Simplify the arithmetic:

2x=310

Simplify the arithmetic:

2x=13

Divide both sides by :

(2x)2=-132

Simplify the fraction:

x=-132

10 additional steps

(6x+10)=-(4x-3)

Expand the parentheses:

(6x+10)=-4x+3

Add to both sides:

(6x+10)+4x=(-4x+3)+4x

Group like terms:

(6x+4x)+10=(-4x+3)+4x

Simplify the arithmetic:

10x+10=(-4x+3)+4x

Group like terms:

10x+10=(-4x+4x)+3

Simplify the arithmetic:

10x+10=3

Subtract from both sides:

(10x+10)-10=3-10

Simplify the arithmetic:

10x=310

Simplify the arithmetic:

10x=7

Divide both sides by :

(10x)10=-710

Simplify the fraction:

x=-710

3. List the solutions

x=-132,-710
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|6x+10|
y=|4x3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.