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Solution - Absolute value equations

Exact form: x=13,1
x=-13 , 1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|6x+1|=|5x12|
without the absolute value bars:

|x|=|y||6x+1|=|5x12|
x=+y(6x+1)=(5x12)
x=y(6x+1)=(5x12)
+x=y(6x+1)=(5x12)
x=y(6x+1)=(5x12)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||6x+1|=|5x12|
x=+y , +x=y(6x+1)=(5x12)
x=y , x=y(6x+1)=(5x12)

2. Solve the two equations for x

7 additional steps

(6x+1)=(5x-12)

Subtract from both sides:

(6x+1)-5x=(5x-12)-5x

Group like terms:

(6x-5x)+1=(5x-12)-5x

Simplify the arithmetic:

x+1=(5x-12)-5x

Group like terms:

x+1=(5x-5x)-12

Simplify the arithmetic:

x+1=12

Subtract from both sides:

(x+1)-1=-12-1

Simplify the arithmetic:

x=121

Simplify the arithmetic:

x=13

11 additional steps

(6x+1)=-(5x-12)

Expand the parentheses:

(6x+1)=-5x+12

Add to both sides:

(6x+1)+5x=(-5x+12)+5x

Group like terms:

(6x+5x)+1=(-5x+12)+5x

Simplify the arithmetic:

11x+1=(-5x+12)+5x

Group like terms:

11x+1=(-5x+5x)+12

Simplify the arithmetic:

11x+1=12

Subtract from both sides:

(11x+1)-1=12-1

Simplify the arithmetic:

11x=121

Simplify the arithmetic:

11x=11

Divide both sides by :

(11x)11=1111

Simplify the fraction:

x=1111

Simplify the fraction:

x=1

3. List the solutions

x=13,1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|6x+1|
y=|5x12|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.