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Solution - Absolute value equations

Exact form: w=-43
w=-\frac{4}{3}
Mixed number form: w=-113
w=-1\frac{1}{3}
Decimal form: w=1.333
w=-1.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|6w2|=|6w+18|
without the absolute value bars:

|x|=|y||6w2|=|6w+18|
x=+y(6w2)=(6w+18)
x=y(6w2)=(6w+18)
+x=y(6w2)=(6w+18)
x=y(6w2)=(6w+18)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||6w2|=|6w+18|
x=+y , +x=y(6w2)=(6w+18)
x=y , x=y(6w2)=(6w+18)

2. Solve the two equations for w

5 additional steps

(6w-2)=(6w+18)

Subtract from both sides:

(6w-2)-6w=(6w+18)-6w

Group like terms:

(6w-6w)-2=(6w+18)-6w

Simplify the arithmetic:

-2=(6w+18)-6w

Group like terms:

-2=(6w-6w)+18

Simplify the arithmetic:

2=18

The statement is false:

2=18

The equation is false so it has no solution.

12 additional steps

(6w-2)=-(6w+18)

Expand the parentheses:

(6w-2)=-6w-18

Add to both sides:

(6w-2)+6w=(-6w-18)+6w

Group like terms:

(6w+6w)-2=(-6w-18)+6w

Simplify the arithmetic:

12w-2=(-6w-18)+6w

Group like terms:

12w-2=(-6w+6w)-18

Simplify the arithmetic:

12w2=18

Add to both sides:

(12w-2)+2=-18+2

Simplify the arithmetic:

12w=18+2

Simplify the arithmetic:

12w=16

Divide both sides by :

(12w)12=-1612

Simplify the fraction:

w=-1612

Find the greatest common factor of the numerator and denominator:

w=(-4·4)(3·4)

Factor out and cancel the greatest common factor:

w=-43

3. Graph

Each line represents the function of one side of the equation:
y=|6w2|
y=|6w+18|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.