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Solution - Absolute value equations

Exact form: u=-2,-29
u=-2 , -\frac{2}{9}
Decimal form: u=2,0.222
u=-2 , -0.222

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|6u+4|=|3u2|
without the absolute value bars:

|x|=|y||6u+4|=|3u2|
x=+y(6u+4)=(3u2)
x=y(6u+4)=(3u2)
+x=y(6u+4)=(3u2)
x=y(6u+4)=(3u2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||6u+4|=|3u2|
x=+y , +x=y(6u+4)=(3u2)
x=y , x=y(6u+4)=(3u2)

2. Solve the two equations for u

11 additional steps

(6u+4)=(3u-2)

Subtract from both sides:

(6u+4)-3u=(3u-2)-3u

Group like terms:

(6u-3u)+4=(3u-2)-3u

Simplify the arithmetic:

3u+4=(3u-2)-3u

Group like terms:

3u+4=(3u-3u)-2

Simplify the arithmetic:

3u+4=2

Subtract from both sides:

(3u+4)-4=-2-4

Simplify the arithmetic:

3u=24

Simplify the arithmetic:

3u=6

Divide both sides by :

(3u)3=-63

Simplify the fraction:

u=-63

Find the greatest common factor of the numerator and denominator:

u=(-2·3)(1·3)

Factor out and cancel the greatest common factor:

u=2

10 additional steps

(6u+4)=-(3u-2)

Expand the parentheses:

(6u+4)=-3u+2

Add to both sides:

(6u+4)+3u=(-3u+2)+3u

Group like terms:

(6u+3u)+4=(-3u+2)+3u

Simplify the arithmetic:

9u+4=(-3u+2)+3u

Group like terms:

9u+4=(-3u+3u)+2

Simplify the arithmetic:

9u+4=2

Subtract from both sides:

(9u+4)-4=2-4

Simplify the arithmetic:

9u=24

Simplify the arithmetic:

9u=2

Divide both sides by :

(9u)9=-29

Simplify the fraction:

u=-29

3. List the solutions

u=-2,-29
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|6u+4|
y=|3u2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.