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Solution - Absolute value equations

Exact form: x=143,2
x=\frac{14}{3} , 2
Mixed number form: x=423,2
x=4\frac{2}{3} , 2
Decimal form: x=4.667,2
x=4.667 , 2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+6|=|2x8|
without the absolute value bars:

|x|=|y||x+6|=|2x8|
x=+y(x+6)=(2x8)
x=y(x+6)=(2x8)
+x=y(x+6)=(2x8)
x=y(x+6)=(2x8)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+6|=|2x8|
x=+y , +x=y(x+6)=(2x8)
x=y , x=y(x+6)=(2x8)

2. Solve the two equations for x

11 additional steps

(-x+6)=(2x-8)

Subtract from both sides:

(-x+6)-2x=(2x-8)-2x

Group like terms:

(-x-2x)+6=(2x-8)-2x

Simplify the arithmetic:

-3x+6=(2x-8)-2x

Group like terms:

-3x+6=(2x-2x)-8

Simplify the arithmetic:

3x+6=8

Subtract from both sides:

(-3x+6)-6=-8-6

Simplify the arithmetic:

3x=86

Simplify the arithmetic:

3x=14

Divide both sides by :

(-3x)-3=-14-3

Cancel out the negatives:

3x3=-14-3

Simplify the fraction:

x=-14-3

Cancel out the negatives:

x=143

8 additional steps

(-x+6)=-(2x-8)

Expand the parentheses:

(-x+6)=-2x+8

Add to both sides:

(-x+6)+2x=(-2x+8)+2x

Group like terms:

(-x+2x)+6=(-2x+8)+2x

Simplify the arithmetic:

x+6=(-2x+8)+2x

Group like terms:

x+6=(-2x+2x)+8

Simplify the arithmetic:

x+6=8

Subtract from both sides:

(x+6)-6=8-6

Simplify the arithmetic:

x=86

Simplify the arithmetic:

x=2

3. List the solutions

x=143,2
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x+6|
y=|2x8|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.