Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=65,6
x=\frac{6}{5} , 6
Mixed number form: x=115,6
x=1\frac{1}{5} , 6
Decimal form: x=1.2,6
x=1.2 , 6

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x+6|=|5x6|
without the absolute value bars:

|x|=|y||5x+6|=|5x6|
x=+y(5x+6)=(5x6)
x=y(5x+6)=(5x6)
+x=y(5x+6)=(5x6)
x=y(5x+6)=(5x6)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x+6|=|5x6|
x=+y , +x=y(5x+6)=(5x6)
x=y , x=y(5x+6)=(5x6)

2. Solve the two equations for x

13 additional steps

(-5x+6)=(5x-6)

Subtract from both sides:

(-5x+6)-5x=(5x-6)-5x

Group like terms:

(-5x-5x)+6=(5x-6)-5x

Simplify the arithmetic:

-10x+6=(5x-6)-5x

Group like terms:

-10x+6=(5x-5x)-6

Simplify the arithmetic:

10x+6=6

Subtract from both sides:

(-10x+6)-6=-6-6

Simplify the arithmetic:

10x=66

Simplify the arithmetic:

10x=12

Divide both sides by :

(-10x)-10=-12-10

Cancel out the negatives:

10x10=-12-10

Simplify the fraction:

x=-12-10

Cancel out the negatives:

x=1210

Find the greatest common factor of the numerator and denominator:

x=(6·2)(5·2)

Factor out and cancel the greatest common factor:

x=65

5 additional steps

(-5x+6)=-(5x-6)

Expand the parentheses:

(-5x+6)=-5x+6

Add to both sides:

(-5x+6)+5x=(-5x+6)+5x

Group like terms:

(-5x+5x)+6=(-5x+6)+5x

Simplify the arithmetic:

6=(-5x+6)+5x

Group like terms:

6=(-5x+5x)+6

Simplify the arithmetic:

6=6

3. List the solutions

x=65,6
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x+6|
y=|5x6|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.