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Solution - Absolute value equations

Exact form: x=1,2
x=1 , 2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x+6|=|3x2|
without the absolute value bars:

|x|=|y||5x+6|=|3x2|
x=+y(5x+6)=(3x2)
x=y(5x+6)=(3x2)
+x=y(5x+6)=(3x2)
x=y(5x+6)=(3x2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x+6|=|3x2|
x=+y , +x=y(5x+6)=(3x2)
x=y , x=y(5x+6)=(3x2)

2. Solve the two equations for x

12 additional steps

(-5x+6)=(3x-2)

Subtract from both sides:

(-5x+6)-3x=(3x-2)-3x

Group like terms:

(-5x-3x)+6=(3x-2)-3x

Simplify the arithmetic:

-8x+6=(3x-2)-3x

Group like terms:

-8x+6=(3x-3x)-2

Simplify the arithmetic:

8x+6=2

Subtract from both sides:

(-8x+6)-6=-2-6

Simplify the arithmetic:

8x=26

Simplify the arithmetic:

8x=8

Divide both sides by :

(-8x)-8=-8-8

Cancel out the negatives:

8x8=-8-8

Simplify the fraction:

x=-8-8

Cancel out the negatives:

x=88

Simplify the fraction:

x=1

14 additional steps

(-5x+6)=-(3x-2)

Expand the parentheses:

(-5x+6)=-3x+2

Add to both sides:

(-5x+6)+3x=(-3x+2)+3x

Group like terms:

(-5x+3x)+6=(-3x+2)+3x

Simplify the arithmetic:

-2x+6=(-3x+2)+3x

Group like terms:

-2x+6=(-3x+3x)+2

Simplify the arithmetic:

2x+6=2

Subtract from both sides:

(-2x+6)-6=2-6

Simplify the arithmetic:

2x=26

Simplify the arithmetic:

2x=4

Divide both sides by :

(-2x)-2=-4-2

Cancel out the negatives:

2x2=-4-2

Simplify the fraction:

x=-4-2

Cancel out the negatives:

x=42

Find the greatest common factor of the numerator and denominator:

x=(2·2)(1·2)

Factor out and cancel the greatest common factor:

x=2

3. List the solutions

x=1,2
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x+6|
y=|3x2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.