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Solution - Absolute value equations

Exact form: w=12
w=\frac{1}{2}
Decimal form: w=0.5
w=0.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2w+6|=|2w+4|
without the absolute value bars:

|x|=|y||2w+6|=|2w+4|
x=+y(2w+6)=(2w+4)
x=y(2w+6)=(2w+4)
+x=y(2w+6)=(2w+4)
x=y(2w+6)=(2w+4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2w+6|=|2w+4|
x=+y , +x=y(2w+6)=(2w+4)
x=y , x=y(2w+6)=(2w+4)

2. Solve the two equations for w

13 additional steps

(-2w+6)=(2w+4)

Subtract from both sides:

(-2w+6)-2w=(2w+4)-2w

Group like terms:

(-2w-2w)+6=(2w+4)-2w

Simplify the arithmetic:

-4w+6=(2w+4)-2w

Group like terms:

-4w+6=(2w-2w)+4

Simplify the arithmetic:

4w+6=4

Subtract from both sides:

(-4w+6)-6=4-6

Simplify the arithmetic:

4w=46

Simplify the arithmetic:

4w=2

Divide both sides by :

(-4w)-4=-2-4

Cancel out the negatives:

4w4=-2-4

Simplify the fraction:

w=-2-4

Cancel out the negatives:

w=24

Find the greatest common factor of the numerator and denominator:

w=(1·2)(2·2)

Factor out and cancel the greatest common factor:

w=12

6 additional steps

(-2w+6)=-(2w+4)

Expand the parentheses:

(-2w+6)=-2w-4

Add to both sides:

(-2w+6)+2w=(-2w-4)+2w

Group like terms:

(-2w+2w)+6=(-2w-4)+2w

Simplify the arithmetic:

6=(-2w-4)+2w

Group like terms:

6=(-2w+2w)-4

Simplify the arithmetic:

6=4

The statement is false:

6=4

The equation is false so it has no solution.

3. List the solutions

w=12
(1 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2w+6|
y=|2w+4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.