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Solution - Absolute value equations

Exact form: z=11,-13
z=11 , -\frac{1}{3}
Decimal form: z=11,0.333
z=11 , -0.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5z4|=|4z+7|
without the absolute value bars:

|x|=|y||5z4|=|4z+7|
x=+y(5z4)=(4z+7)
x=y(5z4)=(4z+7)
+x=y(5z4)=(4z+7)
x=y(5z4)=(4z+7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5z4|=|4z+7|
x=+y , +x=y(5z4)=(4z+7)
x=y , x=y(5z4)=(4z+7)

2. Solve the two equations for z

7 additional steps

(5z-4)=(4z+7)

Subtract from both sides:

(5z-4)-4z=(4z+7)-4z

Group like terms:

(5z-4z)-4=(4z+7)-4z

Simplify the arithmetic:

z-4=(4z+7)-4z

Group like terms:

z-4=(4z-4z)+7

Simplify the arithmetic:

z4=7

Add to both sides:

(z-4)+4=7+4

Simplify the arithmetic:

z=7+4

Simplify the arithmetic:

z=11

12 additional steps

(5z-4)=-(4z+7)

Expand the parentheses:

(5z-4)=-4z-7

Add to both sides:

(5z-4)+4z=(-4z-7)+4z

Group like terms:

(5z+4z)-4=(-4z-7)+4z

Simplify the arithmetic:

9z-4=(-4z-7)+4z

Group like terms:

9z-4=(-4z+4z)-7

Simplify the arithmetic:

9z4=7

Add to both sides:

(9z-4)+4=-7+4

Simplify the arithmetic:

9z=7+4

Simplify the arithmetic:

9z=3

Divide both sides by :

(9z)9=-39

Simplify the fraction:

z=-39

Find the greatest common factor of the numerator and denominator:

z=(-1·3)(3·3)

Factor out and cancel the greatest common factor:

z=-13

3. List the solutions

z=11,-13
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5z4|
y=|4z+7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.