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Solution - Absolute value equations

Exact form: y=-2,27
y=-2 , \frac{2}{7}
Decimal form: y=2,0.286
y=-2 , 0.286

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5y6|=|9y+2|
without the absolute value bars:

|x|=|y||5y6|=|9y+2|
x=+y(5y6)=(9y+2)
x=y(5y6)=(9y+2)
+x=y(5y6)=(9y+2)
x=y(5y6)=(9y+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5y6|=|9y+2|
x=+y , +x=y(5y6)=(9y+2)
x=y , x=y(5y6)=(9y+2)

2. Solve the two equations for y

13 additional steps

(5y-6)=(9y+2)

Subtract from both sides:

(5y-6)-9y=(9y+2)-9y

Group like terms:

(5y-9y)-6=(9y+2)-9y

Simplify the arithmetic:

-4y-6=(9y+2)-9y

Group like terms:

-4y-6=(9y-9y)+2

Simplify the arithmetic:

4y6=2

Add to both sides:

(-4y-6)+6=2+6

Simplify the arithmetic:

4y=2+6

Simplify the arithmetic:

4y=8

Divide both sides by :

(-4y)-4=8-4

Cancel out the negatives:

4y4=8-4

Simplify the fraction:

y=8-4

Move the negative sign from the denominator to the numerator:

y=-84

Find the greatest common factor of the numerator and denominator:

y=(-2·4)(1·4)

Factor out and cancel the greatest common factor:

y=2

12 additional steps

(5y-6)=-(9y+2)

Expand the parentheses:

(5y-6)=-9y-2

Add to both sides:

(5y-6)+9y=(-9y-2)+9y

Group like terms:

(5y+9y)-6=(-9y-2)+9y

Simplify the arithmetic:

14y-6=(-9y-2)+9y

Group like terms:

14y-6=(-9y+9y)-2

Simplify the arithmetic:

14y6=2

Add to both sides:

(14y-6)+6=-2+6

Simplify the arithmetic:

14y=2+6

Simplify the arithmetic:

14y=4

Divide both sides by :

(14y)14=414

Simplify the fraction:

y=414

Find the greatest common factor of the numerator and denominator:

y=(2·2)(7·2)

Factor out and cancel the greatest common factor:

y=27

3. List the solutions

y=-2,27
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5y6|
y=|9y+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.