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Solution - Absolute value equations

Exact form: y=35,-3
y=\frac{3}{5} , -3
Decimal form: y=0.6,3
y=0.6 , -3

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5y3|=|5y+3|
without the absolute value bars:

|x|=|y||5y3|=|5y+3|
x=+y(5y3)=(5y+3)
x=y(5y3)=(5y+3)
+x=y(5y3)=(5y+3)
x=y(5y3)=(5y+3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5y3|=|5y+3|
x=+y , +x=y(5y3)=(5y+3)
x=y , x=y(5y3)=(5y+3)

2. Solve the two equations for y

11 additional steps

(5y-3)=(-5y+3)

Add to both sides:

(5y-3)+5y=(-5y+3)+5y

Group like terms:

(5y+5y)-3=(-5y+3)+5y

Simplify the arithmetic:

10y-3=(-5y+3)+5y

Group like terms:

10y-3=(-5y+5y)+3

Simplify the arithmetic:

10y3=3

Add to both sides:

(10y-3)+3=3+3

Simplify the arithmetic:

10y=3+3

Simplify the arithmetic:

10y=6

Divide both sides by :

(10y)10=610

Simplify the fraction:

y=610

Find the greatest common factor of the numerator and denominator:

y=(3·2)(5·2)

Factor out and cancel the greatest common factor:

y=35

5 additional steps

(5y-3)=-(-5y+3)

Expand the parentheses:

(5y-3)=5y-3

Subtract from both sides:

(5y-3)-5y=(5y-3)-5y

Group like terms:

(5y-5y)-3=(5y-3)-5y

Simplify the arithmetic:

-3=(5y-3)-5y

Group like terms:

-3=(5y-5y)-3

Simplify the arithmetic:

3=3

3. List the solutions

y=35,-3
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5y3|
y=|5y+3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.