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Solution - Absolute value equations

Exact form: x=34,314
x=\frac{3}{4} , \frac{3}{14}
Decimal form: x=0.75,0.214
x=0.75 , 0.214

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|5x||9x3|=0

Add |9x3| to both sides of the equation:

|5x||9x3|+|9x3|=|9x3|

Simplify the arithmetic

|5x|=|9x3|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x|=|9x3|
without the absolute value bars:

|x|=|y||5x|=|9x3|
x=+y(5x)=(9x3)
x=y(5x)=((9x3))
+x=y(5x)=(9x3)
x=y(5x)=(9x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x|=|9x3|
x=+y , +x=y(5x)=(9x3)
x=y , x=y(5x)=((9x3))

3. Solve the two equations for x

7 additional steps

5x=(9x-3)

Subtract from both sides:

(5x)-9x=(9x-3)-9x

Simplify the arithmetic:

-4x=(9x-3)-9x

Group like terms:

-4x=(9x-9x)-3

Simplify the arithmetic:

4x=3

Divide both sides by :

(-4x)-4=-3-4

Cancel out the negatives:

4x4=-3-4

Simplify the fraction:

x=-3-4

Cancel out the negatives:

x=34

6 additional steps

5x=-(9x-3)

Expand the parentheses:

5x=9x+3

Add to both sides:

(5x)+9x=(-9x+3)+9x

Simplify the arithmetic:

14x=(-9x+3)+9x

Group like terms:

14x=(-9x+9x)+3

Simplify the arithmetic:

14x=3

Divide both sides by :

(14x)14=314

Simplify the fraction:

x=314

4. List the solutions

x=34,314
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|5x|
y=|9x3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.