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Solution - Absolute value equations

Exact form: x=3,23
x=3 , \frac{2}{3}
Decimal form: x=3,0.667
x=3 , 0.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x8|=|x+4|
without the absolute value bars:

|x|=|y||5x8|=|x+4|
x=+y(5x8)=(x+4)
x=y(5x8)=(x+4)
+x=y(5x8)=(x+4)
x=y(5x8)=(x+4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x8|=|x+4|
x=+y , +x=y(5x8)=(x+4)
x=y , x=y(5x8)=(x+4)

2. Solve the two equations for x

11 additional steps

(5x-8)=(x+4)

Subtract from both sides:

(5x-8)-x=(x+4)-x

Group like terms:

(5x-x)-8=(x+4)-x

Simplify the arithmetic:

4x-8=(x+4)-x

Group like terms:

4x-8=(x-x)+4

Simplify the arithmetic:

4x8=4

Add to both sides:

(4x-8)+8=4+8

Simplify the arithmetic:

4x=4+8

Simplify the arithmetic:

4x=12

Divide both sides by :

(4x)4=124

Simplify the fraction:

x=124

Find the greatest common factor of the numerator and denominator:

x=(3·4)(1·4)

Factor out and cancel the greatest common factor:

x=3

12 additional steps

(5x-8)=-(x+4)

Expand the parentheses:

(5x-8)=-x-4

Add to both sides:

(5x-8)+x=(-x-4)+x

Group like terms:

(5x+x)-8=(-x-4)+x

Simplify the arithmetic:

6x-8=(-x-4)+x

Group like terms:

6x-8=(-x+x)-4

Simplify the arithmetic:

6x8=4

Add to both sides:

(6x-8)+8=-4+8

Simplify the arithmetic:

6x=4+8

Simplify the arithmetic:

6x=4

Divide both sides by :

(6x)6=46

Simplify the fraction:

x=46

Find the greatest common factor of the numerator and denominator:

x=(2·2)(3·2)

Factor out and cancel the greatest common factor:

x=23

3. List the solutions

x=3,23
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x8|
y=|x+4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.