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Solution - Absolute value equations

Exact form: x=0,169
x=0 , \frac{16}{9}
Mixed number form: x=0,179
x=0 , 1\frac{7}{9}
Decimal form: x=0,1.778
x=0 , 1.778

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x8|=|4x8|
without the absolute value bars:

|x|=|y||5x8|=|4x8|
x=+y(5x8)=(4x8)
x=y(5x8)=(4x8)
+x=y(5x8)=(4x8)
x=y(5x8)=(4x8)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x8|=|4x8|
x=+y , +x=y(5x8)=(4x8)
x=y , x=y(5x8)=(4x8)

2. Solve the two equations for x

7 additional steps

(5x-8)=(4x-8)

Subtract from both sides:

(5x-8)-4x=(4x-8)-4x

Group like terms:

(5x-4x)-8=(4x-8)-4x

Simplify the arithmetic:

x-8=(4x-8)-4x

Group like terms:

x-8=(4x-4x)-8

Simplify the arithmetic:

x8=8

Add to both sides:

(x-8)+8=-8+8

Simplify the arithmetic:

x=8+8

Simplify the arithmetic:

x=0

10 additional steps

(5x-8)=-(4x-8)

Expand the parentheses:

(5x-8)=-4x+8

Add to both sides:

(5x-8)+4x=(-4x+8)+4x

Group like terms:

(5x+4x)-8=(-4x+8)+4x

Simplify the arithmetic:

9x-8=(-4x+8)+4x

Group like terms:

9x-8=(-4x+4x)+8

Simplify the arithmetic:

9x8=8

Add to both sides:

(9x-8)+8=8+8

Simplify the arithmetic:

9x=8+8

Simplify the arithmetic:

9x=16

Divide both sides by :

(9x)9=169

Simplify the fraction:

x=169

3. List the solutions

x=0,169
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x8|
y=|4x8|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.