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Solution - Absolute value equations

Exact form: x=4,34
x=4 , \frac{3}{4}
Decimal form: x=4,0.75
x=4 , 0.75

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x7|=|3x+1|
without the absolute value bars:

|x|=|y||5x7|=|3x+1|
x=+y(5x7)=(3x+1)
x=y(5x7)=(3x+1)
+x=y(5x7)=(3x+1)
x=y(5x7)=(3x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x7|=|3x+1|
x=+y , +x=y(5x7)=(3x+1)
x=y , x=y(5x7)=(3x+1)

2. Solve the two equations for x

11 additional steps

(5x-7)=(3x+1)

Subtract from both sides:

(5x-7)-3x=(3x+1)-3x

Group like terms:

(5x-3x)-7=(3x+1)-3x

Simplify the arithmetic:

2x-7=(3x+1)-3x

Group like terms:

2x-7=(3x-3x)+1

Simplify the arithmetic:

2x7=1

Add to both sides:

(2x-7)+7=1+7

Simplify the arithmetic:

2x=1+7

Simplify the arithmetic:

2x=8

Divide both sides by :

(2x)2=82

Simplify the fraction:

x=82

Find the greatest common factor of the numerator and denominator:

x=(4·2)(1·2)

Factor out and cancel the greatest common factor:

x=4

12 additional steps

(5x-7)=-(3x+1)

Expand the parentheses:

(5x-7)=-3x-1

Add to both sides:

(5x-7)+3x=(-3x-1)+3x

Group like terms:

(5x+3x)-7=(-3x-1)+3x

Simplify the arithmetic:

8x-7=(-3x-1)+3x

Group like terms:

8x-7=(-3x+3x)-1

Simplify the arithmetic:

8x7=1

Add to both sides:

(8x-7)+7=-1+7

Simplify the arithmetic:

8x=1+7

Simplify the arithmetic:

8x=6

Divide both sides by :

(8x)8=68

Simplify the fraction:

x=68

Find the greatest common factor of the numerator and denominator:

x=(3·2)(4·2)

Factor out and cancel the greatest common factor:

x=34

3. List the solutions

x=4,34
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x7|
y=|3x+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.