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Solution - Absolute value equations

Exact form: x=83,-1
x=\frac{8}{3} , -1
Mixed number form: x=223,-1
x=2\frac{2}{3} , -1
Decimal form: x=2.667,1
x=2.667 , -1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x6|=|x+10|
without the absolute value bars:

|x|=|y||5x6|=|x+10|
x=+y(5x6)=(x+10)
x=y(5x6)=(x+10)
+x=y(5x6)=(x+10)
x=y(5x6)=(x+10)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x6|=|x+10|
x=+y , +x=y(5x6)=(x+10)
x=y , x=y(5x6)=(x+10)

2. Solve the two equations for x

11 additional steps

(5x-6)=(-x+10)

Add to both sides:

(5x-6)+x=(-x+10)+x

Group like terms:

(5x+x)-6=(-x+10)+x

Simplify the arithmetic:

6x-6=(-x+10)+x

Group like terms:

6x-6=(-x+x)+10

Simplify the arithmetic:

6x6=10

Add to both sides:

(6x-6)+6=10+6

Simplify the arithmetic:

6x=10+6

Simplify the arithmetic:

6x=16

Divide both sides by :

(6x)6=166

Simplify the fraction:

x=166

Find the greatest common factor of the numerator and denominator:

x=(8·2)(3·2)

Factor out and cancel the greatest common factor:

x=83

11 additional steps

(5x-6)=-(-x+10)

Expand the parentheses:

(5x-6)=x-10

Subtract from both sides:

(5x-6)-x=(x-10)-x

Group like terms:

(5x-x)-6=(x-10)-x

Simplify the arithmetic:

4x-6=(x-10)-x

Group like terms:

4x-6=(x-x)-10

Simplify the arithmetic:

4x6=10

Add to both sides:

(4x-6)+6=-10+6

Simplify the arithmetic:

4x=10+6

Simplify the arithmetic:

4x=4

Divide both sides by :

(4x)4=-44

Simplify the fraction:

x=-44

Simplify the fraction:

x=1

3. List the solutions

x=83,-1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x6|
y=|x+10|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.