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Solution - Absolute value equations

Exact form: x=23,87
x=\frac{2}{3} , \frac{8}{7}
Mixed number form: x=23,117
x=\frac{2}{3} , 1\frac{1}{7}
Decimal form: x=0.667,1.143
x=0.667 , 1.143

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|5x5|+|2x+3|=0

Add |2x+3| to both sides of the equation:

|5x5|+|2x+3||2x+3|=|2x+3|

Simplify the arithmetic

|5x5|=|2x+3|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x5|=|2x+3|
without the absolute value bars:

|x|=|y||5x5|=|2x+3|
x=+y(5x5)=(2x+3)
x=y(5x5)=(2x+3)
+x=y(5x5)=(2x+3)
x=y(5x5)=(2x+3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x5|=|2x+3|
x=+y , +x=y(5x5)=(2x+3)
x=y , x=y(5x5)=(2x+3)

3. Solve the two equations for x

10 additional steps

(5x-5)=-(-2x+3)

Expand the parentheses:

(5x-5)=2x-3

Subtract from both sides:

(5x-5)-2x=(2x-3)-2x

Group like terms:

(5x-2x)-5=(2x-3)-2x

Simplify the arithmetic:

3x-5=(2x-3)-2x

Group like terms:

3x-5=(2x-2x)-3

Simplify the arithmetic:

3x5=3

Add to both sides:

(3x-5)+5=-3+5

Simplify the arithmetic:

3x=3+5

Simplify the arithmetic:

3x=2

Divide both sides by :

(3x)3=23

Simplify the fraction:

x=23

10 additional steps

(5x-5)=-(-(-2x+3))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(5x-5)=-2x+3

Add to both sides:

(5x-5)+2x=(-2x+3)+2x

Group like terms:

(5x+2x)-5=(-2x+3)+2x

Simplify the arithmetic:

7x-5=(-2x+3)+2x

Group like terms:

7x-5=(-2x+2x)+3

Simplify the arithmetic:

7x5=3

Add to both sides:

(7x-5)+5=3+5

Simplify the arithmetic:

7x=3+5

Simplify the arithmetic:

7x=8

Divide both sides by :

(7x)7=87

Simplify the fraction:

x=87

4. List the solutions

x=23,87
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|5x5|
y=|2x+3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.