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Solution - Absolute value equations

Exact form: x=-1,27
x=-1 , \frac{2}{7}
Decimal form: x=1,0.286
x=-1 , 0.286

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x4|=|9x|
without the absolute value bars:

|x|=|y||5x4|=|9x|
x=+y(5x4)=(9x)
x=y(5x4)=(9x)
+x=y(5x4)=(9x)
x=y(5x4)=(9x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x4|=|9x|
x=+y , +x=y(5x4)=(9x)
x=y , x=y(5x4)=(9x)

2. Solve the two equations for x

11 additional steps

(5x-4)=9x

Subtract from both sides:

(5x-4)-9x=(9x)-9x

Group like terms:

(5x-9x)-4=(9x)-9x

Simplify the arithmetic:

-4x-4=(9x)-9x

Simplify the arithmetic:

4x4=0

Add to both sides:

(-4x-4)+4=0+4

Simplify the arithmetic:

4x=0+4

Simplify the arithmetic:

4x=4

Divide both sides by :

(-4x)-4=4-4

Cancel out the negatives:

4x4=4-4

Simplify the fraction:

x=4-4

Move the negative sign from the denominator to the numerator:

x=-44

Simplify the fraction:

x=1

9 additional steps

(5x-4)=-9x

Add to both sides:

(5x-4)+4=(-9x)+4

Simplify the arithmetic:

5x=(-9x)+4

Add to both sides:

(5x)+9x=((-9x)+4)+9x

Simplify the arithmetic:

14x=((-9x)+4)+9x

Group like terms:

14x=(-9x+9x)+4

Simplify the arithmetic:

14x=4

Divide both sides by :

(14x)14=414

Simplify the fraction:

x=414

Find the greatest common factor of the numerator and denominator:

x=(2·2)(7·2)

Factor out and cancel the greatest common factor:

x=27

3. List the solutions

x=-1,27
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x4|
y=|9x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.