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Solution - Absolute value equations

Exact form: x=34,12
x=\frac{3}{4} , \frac{1}{2}
Decimal form: x=0.75,0.5
x=0.75 , 0.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|5x3||x|=0

Add |x| to both sides of the equation:

|5x3||x|+|x|=|x|

Simplify the arithmetic

|5x3|=|x|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x3|=|x|
without the absolute value bars:

|x|=|y||5x3|=|x|
x=+y(5x3)=(x)
x=y(5x3)=((x))
+x=y(5x3)=(x)
x=y(5x3)=(x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x3|=|x|
x=+y , +x=y(5x3)=(x)
x=y , x=y(5x3)=((x))

3. Solve the two equations for x

8 additional steps

(5x-3)=x

Subtract from both sides:

(5x-3)-x=x-x

Group like terms:

(5x-x)-3=x-x

Simplify the arithmetic:

4x3=xx

Simplify the arithmetic:

4x3=0

Add to both sides:

(4x-3)+3=0+3

Simplify the arithmetic:

4x=0+3

Simplify the arithmetic:

4x=3

Divide both sides by :

(4x)4=34

Simplify the fraction:

x=34

10 additional steps

(5x-3)=-x

Add to both sides:

(5x-3)+x=-x+x

Group like terms:

(5x+x)-3=-x+x

Simplify the arithmetic:

6x3=x+x

Simplify the arithmetic:

6x3=0

Add to both sides:

(6x-3)+3=0+3

Simplify the arithmetic:

6x=0+3

Simplify the arithmetic:

6x=3

Divide both sides by :

(6x)6=36

Simplify the fraction:

x=36

Find the greatest common factor of the numerator and denominator:

x=(1·3)(2·3)

Factor out and cancel the greatest common factor:

x=12

4. List the solutions

x=34,12
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|5x3|
y=|x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.