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Solution - Absolute value equations

Exact form: x=10,-49
x=10 , -\frac{4}{9}
Decimal form: x=10,0.444
x=10 , -0.444

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|5x3||4x+7|=0

Add |4x+7| to both sides of the equation:

|5x3||4x+7|+|4x+7|=|4x+7|

Simplify the arithmetic

|5x3|=|4x+7|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x3|=|4x+7|
without the absolute value bars:

|x|=|y||5x3|=|4x+7|
x=+y(5x3)=(4x+7)
x=y(5x3)=((4x+7))
+x=y(5x3)=(4x+7)
x=y(5x3)=(4x+7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x3|=|4x+7|
x=+y , +x=y(5x3)=(4x+7)
x=y , x=y(5x3)=((4x+7))

3. Solve the two equations for x

7 additional steps

(5x-3)=(4x+7)

Subtract from both sides:

(5x-3)-4x=(4x+7)-4x

Group like terms:

(5x-4x)-3=(4x+7)-4x

Simplify the arithmetic:

x-3=(4x+7)-4x

Group like terms:

x-3=(4x-4x)+7

Simplify the arithmetic:

x3=7

Add to both sides:

(x-3)+3=7+3

Simplify the arithmetic:

x=7+3

Simplify the arithmetic:

x=10

10 additional steps

(5x-3)=-(4x+7)

Expand the parentheses:

(5x-3)=-4x-7

Add to both sides:

(5x-3)+4x=(-4x-7)+4x

Group like terms:

(5x+4x)-3=(-4x-7)+4x

Simplify the arithmetic:

9x-3=(-4x-7)+4x

Group like terms:

9x-3=(-4x+4x)-7

Simplify the arithmetic:

9x3=7

Add to both sides:

(9x-3)+3=-7+3

Simplify the arithmetic:

9x=7+3

Simplify the arithmetic:

9x=4

Divide both sides by :

(9x)9=-49

Simplify the fraction:

x=-49

4. List the solutions

x=10,-49
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|5x3|
y=|4x+7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.