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Solution - Absolute value equations

Exact form: x=2,-13
x=2 , -\frac{1}{3}
Decimal form: x=2,0.333
x=2 , -0.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x3|=|x+5|
without the absolute value bars:

|x|=|y||5x3|=|x+5|
x=+y(5x3)=(x+5)
x=y(5x3)=(x+5)
+x=y(5x3)=(x+5)
x=y(5x3)=(x+5)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x3|=|x+5|
x=+y , +x=y(5x3)=(x+5)
x=y , x=y(5x3)=(x+5)

2. Solve the two equations for x

11 additional steps

(5x-3)=(x+5)

Subtract from both sides:

(5x-3)-x=(x+5)-x

Group like terms:

(5x-x)-3=(x+5)-x

Simplify the arithmetic:

4x-3=(x+5)-x

Group like terms:

4x-3=(x-x)+5

Simplify the arithmetic:

4x3=5

Add to both sides:

(4x-3)+3=5+3

Simplify the arithmetic:

4x=5+3

Simplify the arithmetic:

4x=8

Divide both sides by :

(4x)4=84

Simplify the fraction:

x=84

Find the greatest common factor of the numerator and denominator:

x=(2·4)(1·4)

Factor out and cancel the greatest common factor:

x=2

12 additional steps

(5x-3)=-(x+5)

Expand the parentheses:

(5x-3)=-x-5

Add to both sides:

(5x-3)+x=(-x-5)+x

Group like terms:

(5x+x)-3=(-x-5)+x

Simplify the arithmetic:

6x-3=(-x-5)+x

Group like terms:

6x-3=(-x+x)-5

Simplify the arithmetic:

6x3=5

Add to both sides:

(6x-3)+3=-5+3

Simplify the arithmetic:

6x=5+3

Simplify the arithmetic:

6x=2

Divide both sides by :

(6x)6=-26

Simplify the fraction:

x=-26

Find the greatest common factor of the numerator and denominator:

x=(-1·2)(3·2)

Factor out and cancel the greatest common factor:

x=-13

3. List the solutions

x=2,-13
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x3|
y=|x+5|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.