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Solution - Absolute value equations

Exact form: x=-14,514
x=-\frac{1}{4} , \frac{5}{14}
Decimal form: x=0.25,0.357
x=-0.25 , 0.357

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x3|=|9x2|
without the absolute value bars:

|x|=|y||5x3|=|9x2|
x=+y(5x3)=(9x2)
x=y(5x3)=(9x2)
+x=y(5x3)=(9x2)
x=y(5x3)=(9x2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x3|=|9x2|
x=+y , +x=y(5x3)=(9x2)
x=y , x=y(5x3)=(9x2)

2. Solve the two equations for x

11 additional steps

(5x-3)=(9x-2)

Subtract from both sides:

(5x-3)-9x=(9x-2)-9x

Group like terms:

(5x-9x)-3=(9x-2)-9x

Simplify the arithmetic:

-4x-3=(9x-2)-9x

Group like terms:

-4x-3=(9x-9x)-2

Simplify the arithmetic:

4x3=2

Add to both sides:

(-4x-3)+3=-2+3

Simplify the arithmetic:

4x=2+3

Simplify the arithmetic:

4x=1

Divide both sides by :

(-4x)-4=1-4

Cancel out the negatives:

4x4=1-4

Simplify the fraction:

x=1-4

Move the negative sign from the denominator to the numerator:

x=-14

10 additional steps

(5x-3)=-(9x-2)

Expand the parentheses:

(5x-3)=-9x+2

Add to both sides:

(5x-3)+9x=(-9x+2)+9x

Group like terms:

(5x+9x)-3=(-9x+2)+9x

Simplify the arithmetic:

14x-3=(-9x+2)+9x

Group like terms:

14x-3=(-9x+9x)+2

Simplify the arithmetic:

14x3=2

Add to both sides:

(14x-3)+3=2+3

Simplify the arithmetic:

14x=2+3

Simplify the arithmetic:

14x=5

Divide both sides by :

(14x)14=514

Simplify the fraction:

x=514

3. List the solutions

x=-14,514
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x3|
y=|9x2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.