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Solution - Absolute value equations

Exact form: x=-52,112
x=-\frac{5}{2} , \frac{1}{12}
Mixed number form: x=-212,112
x=-2\frac{1}{2} , \frac{1}{12}
Decimal form: x=2.5,0.083
x=-2.5 , 0.083

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x3|=|7x+2|
without the absolute value bars:

|x|=|y||5x3|=|7x+2|
x=+y(5x3)=(7x+2)
x=y(5x3)=(7x+2)
+x=y(5x3)=(7x+2)
x=y(5x3)=(7x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x3|=|7x+2|
x=+y , +x=y(5x3)=(7x+2)
x=y , x=y(5x3)=(7x+2)

2. Solve the two equations for x

11 additional steps

(5x-3)=(7x+2)

Subtract from both sides:

(5x-3)-7x=(7x+2)-7x

Group like terms:

(5x-7x)-3=(7x+2)-7x

Simplify the arithmetic:

-2x-3=(7x+2)-7x

Group like terms:

-2x-3=(7x-7x)+2

Simplify the arithmetic:

2x3=2

Add to both sides:

(-2x-3)+3=2+3

Simplify the arithmetic:

2x=2+3

Simplify the arithmetic:

2x=5

Divide both sides by :

(-2x)-2=5-2

Cancel out the negatives:

2x2=5-2

Simplify the fraction:

x=5-2

Move the negative sign from the denominator to the numerator:

x=-52

10 additional steps

(5x-3)=-(7x+2)

Expand the parentheses:

(5x-3)=-7x-2

Add to both sides:

(5x-3)+7x=(-7x-2)+7x

Group like terms:

(5x+7x)-3=(-7x-2)+7x

Simplify the arithmetic:

12x-3=(-7x-2)+7x

Group like terms:

12x-3=(-7x+7x)-2

Simplify the arithmetic:

12x3=2

Add to both sides:

(12x-3)+3=-2+3

Simplify the arithmetic:

12x=2+3

Simplify the arithmetic:

12x=1

Divide both sides by :

(12x)12=112

Simplify the fraction:

x=112

3. List the solutions

x=-52,112
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x3|
y=|7x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.