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Solution - Absolute value equations

Exact form: x=-2,16
x=-2 , \frac{1}{6}
Decimal form: x=2,0.167
x=-2 , 0.167

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x3|=|7x+1|
without the absolute value bars:

|x|=|y||5x3|=|7x+1|
x=+y(5x3)=(7x+1)
x=y(5x3)=(7x+1)
+x=y(5x3)=(7x+1)
x=y(5x3)=(7x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x3|=|7x+1|
x=+y , +x=y(5x3)=(7x+1)
x=y , x=y(5x3)=(7x+1)

2. Solve the two equations for x

13 additional steps

(5x-3)=(7x+1)

Subtract from both sides:

(5x-3)-7x=(7x+1)-7x

Group like terms:

(5x-7x)-3=(7x+1)-7x

Simplify the arithmetic:

-2x-3=(7x+1)-7x

Group like terms:

-2x-3=(7x-7x)+1

Simplify the arithmetic:

2x3=1

Add to both sides:

(-2x-3)+3=1+3

Simplify the arithmetic:

2x=1+3

Simplify the arithmetic:

2x=4

Divide both sides by :

(-2x)-2=4-2

Cancel out the negatives:

2x2=4-2

Simplify the fraction:

x=4-2

Move the negative sign from the denominator to the numerator:

x=-42

Find the greatest common factor of the numerator and denominator:

x=(-2·2)(1·2)

Factor out and cancel the greatest common factor:

x=2

12 additional steps

(5x-3)=-(7x+1)

Expand the parentheses:

(5x-3)=-7x-1

Add to both sides:

(5x-3)+7x=(-7x-1)+7x

Group like terms:

(5x+7x)-3=(-7x-1)+7x

Simplify the arithmetic:

12x-3=(-7x-1)+7x

Group like terms:

12x-3=(-7x+7x)-1

Simplify the arithmetic:

12x3=1

Add to both sides:

(12x-3)+3=-1+3

Simplify the arithmetic:

12x=1+3

Simplify the arithmetic:

12x=2

Divide both sides by :

(12x)12=212

Simplify the fraction:

x=212

Find the greatest common factor of the numerator and denominator:

x=(1·2)(6·2)

Factor out and cancel the greatest common factor:

x=16

3. List the solutions

x=-2,16
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x3|
y=|7x+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.