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Solution - Absolute value equations

Exact form: x=-12,58
x=-\frac{1}{2} , \frac{5}{8}
Decimal form: x=0.5,0.625
x=-0.5 , 0.625

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x2|=3|x1|
without the absolute value bars:

|x|=|y||5x2|=3|x1|
x=+y(5x2)=3(x1)
x=y(5x2)=3((x1))
+x=y(5x2)=3(x1)
x=y(5x2)=3(x1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x2|=3|x1|
x=+y , +x=y(5x2)=3(x1)
x=y , x=y(5x2)=3((x1))

2. Solve the two equations for x

11 additional steps

(5x-2)=3·(x-1)

Expand the parentheses:

(5x-2)=3x+3·-1

Simplify the arithmetic:

(5x-2)=3x-3

Subtract from both sides:

(5x-2)-3x=(3x-3)-3x

Group like terms:

(5x-3x)-2=(3x-3)-3x

Simplify the arithmetic:

2x-2=(3x-3)-3x

Group like terms:

2x-2=(3x-3x)-3

Simplify the arithmetic:

2x2=3

Add to both sides:

(2x-2)+2=-3+2

Simplify the arithmetic:

2x=3+2

Simplify the arithmetic:

2x=1

Divide both sides by :

(2x)2=-12

Simplify the fraction:

x=-12

14 additional steps

(5x-2)=3·(-(x-1))

Expand the parentheses:

(5x-2)=3·(-x+1)

(5x-2)=3·-x+3·1

Group like terms:

(5x-2)=(3·-1)x+3·1

Multiply the coefficients:

(5x-2)=-3x+3·1

Simplify the arithmetic:

(5x-2)=-3x+3

Add to both sides:

(5x-2)+3x=(-3x+3)+3x

Group like terms:

(5x+3x)-2=(-3x+3)+3x

Simplify the arithmetic:

8x-2=(-3x+3)+3x

Group like terms:

8x-2=(-3x+3x)+3

Simplify the arithmetic:

8x2=3

Add to both sides:

(8x-2)+2=3+2

Simplify the arithmetic:

8x=3+2

Simplify the arithmetic:

8x=5

Divide both sides by :

(8x)8=58

Simplify the fraction:

x=58

3. List the solutions

x=-12,58
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x2|
y=3|x1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.