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Solution - Absolute value equations

Exact form: x=-14,314
x=-\frac{1}{4} , \frac{3}{14}
Decimal form: x=0.25,0.214
x=-0.25 , 0.214

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x2|=|9x1|
without the absolute value bars:

|x|=|y||5x2|=|9x1|
x=+y(5x2)=(9x1)
x=y(5x2)=(9x1)
+x=y(5x2)=(9x1)
x=y(5x2)=(9x1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x2|=|9x1|
x=+y , +x=y(5x2)=(9x1)
x=y , x=y(5x2)=(9x1)

2. Solve the two equations for x

11 additional steps

(5x-2)=(9x-1)

Subtract from both sides:

(5x-2)-9x=(9x-1)-9x

Group like terms:

(5x-9x)-2=(9x-1)-9x

Simplify the arithmetic:

-4x-2=(9x-1)-9x

Group like terms:

-4x-2=(9x-9x)-1

Simplify the arithmetic:

4x2=1

Add to both sides:

(-4x-2)+2=-1+2

Simplify the arithmetic:

4x=1+2

Simplify the arithmetic:

4x=1

Divide both sides by :

(-4x)-4=1-4

Cancel out the negatives:

4x4=1-4

Simplify the fraction:

x=1-4

Move the negative sign from the denominator to the numerator:

x=-14

10 additional steps

(5x-2)=-(9x-1)

Expand the parentheses:

(5x-2)=-9x+1

Add to both sides:

(5x-2)+9x=(-9x+1)+9x

Group like terms:

(5x+9x)-2=(-9x+1)+9x

Simplify the arithmetic:

14x-2=(-9x+1)+9x

Group like terms:

14x-2=(-9x+9x)+1

Simplify the arithmetic:

14x2=1

Add to both sides:

(14x-2)+2=1+2

Simplify the arithmetic:

14x=1+2

Simplify the arithmetic:

14x=3

Divide both sides by :

(14x)14=314

Simplify the fraction:

x=314

3. List the solutions

x=-14,314
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x2|
y=|9x1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.