Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=73,-37
x=\frac{7}{3} , -\frac{3}{7}
Mixed number form: x=213,-37
x=2\frac{1}{3} , -\frac{3}{7}
Decimal form: x=2.333,0.429
x=2.333 , -0.429

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x2|=|2x+5|
without the absolute value bars:

|x|=|y||5x2|=|2x+5|
x=+y(5x2)=(2x+5)
x=y(5x2)=(2x+5)
+x=y(5x2)=(2x+5)
x=y(5x2)=(2x+5)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x2|=|2x+5|
x=+y , +x=y(5x2)=(2x+5)
x=y , x=y(5x2)=(2x+5)

2. Solve the two equations for x

9 additional steps

(5x-2)=(2x+5)

Subtract from both sides:

(5x-2)-2x=(2x+5)-2x

Group like terms:

(5x-2x)-2=(2x+5)-2x

Simplify the arithmetic:

3x-2=(2x+5)-2x

Group like terms:

3x-2=(2x-2x)+5

Simplify the arithmetic:

3x2=5

Add to both sides:

(3x-2)+2=5+2

Simplify the arithmetic:

3x=5+2

Simplify the arithmetic:

3x=7

Divide both sides by :

(3x)3=73

Simplify the fraction:

x=73

10 additional steps

(5x-2)=-(2x+5)

Expand the parentheses:

(5x-2)=-2x-5

Add to both sides:

(5x-2)+2x=(-2x-5)+2x

Group like terms:

(5x+2x)-2=(-2x-5)+2x

Simplify the arithmetic:

7x-2=(-2x-5)+2x

Group like terms:

7x-2=(-2x+2x)-5

Simplify the arithmetic:

7x2=5

Add to both sides:

(7x-2)+2=-5+2

Simplify the arithmetic:

7x=5+2

Simplify the arithmetic:

7x=3

Divide both sides by :

(7x)7=-37

Simplify the fraction:

x=-37

3. List the solutions

x=73,-37
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x2|
y=|2x+5|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.