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Solution - Absolute value equations

Exact form: x=-292,34
x=-\frac{29}{2} , \frac{3}{4}
Mixed number form: x=-1412,34
x=-14\frac{1}{2} , \frac{3}{4}
Decimal form: x=14.5,0.75
x=-14.5 , 0.75

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x19|=|7x+10|
without the absolute value bars:

|x|=|y||5x19|=|7x+10|
x=+y(5x19)=(7x+10)
x=y(5x19)=(7x+10)
+x=y(5x19)=(7x+10)
x=y(5x19)=(7x+10)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x19|=|7x+10|
x=+y , +x=y(5x19)=(7x+10)
x=y , x=y(5x19)=(7x+10)

2. Solve the two equations for x

11 additional steps

(5x-19)=(7x+10)

Subtract from both sides:

(5x-19)-7x=(7x+10)-7x

Group like terms:

(5x-7x)-19=(7x+10)-7x

Simplify the arithmetic:

-2x-19=(7x+10)-7x

Group like terms:

-2x-19=(7x-7x)+10

Simplify the arithmetic:

2x19=10

Add to both sides:

(-2x-19)+19=10+19

Simplify the arithmetic:

2x=10+19

Simplify the arithmetic:

2x=29

Divide both sides by :

(-2x)-2=29-2

Cancel out the negatives:

2x2=29-2

Simplify the fraction:

x=29-2

Move the negative sign from the denominator to the numerator:

x=-292

12 additional steps

(5x-19)=-(7x+10)

Expand the parentheses:

(5x-19)=-7x-10

Add to both sides:

(5x-19)+7x=(-7x-10)+7x

Group like terms:

(5x+7x)-19=(-7x-10)+7x

Simplify the arithmetic:

12x-19=(-7x-10)+7x

Group like terms:

12x-19=(-7x+7x)-10

Simplify the arithmetic:

12x19=10

Add to both sides:

(12x-19)+19=-10+19

Simplify the arithmetic:

12x=10+19

Simplify the arithmetic:

12x=9

Divide both sides by :

(12x)12=912

Simplify the fraction:

x=912

Find the greatest common factor of the numerator and denominator:

x=(3·3)(4·3)

Factor out and cancel the greatest common factor:

x=34

3. List the solutions

x=-292,34
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x19|
y=|7x+10|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.