Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=-293,313
x=-\frac{29}{3} , \frac{3}{13}
Mixed number form: x=-923,313
x=-9\frac{2}{3} , \frac{3}{13}
Decimal form: x=9.667,0.231
x=-9.667 , 0.231

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x16|=|8x+13|
without the absolute value bars:

|x|=|y||5x16|=|8x+13|
x=+y(5x16)=(8x+13)
x=y(5x16)=(8x+13)
+x=y(5x16)=(8x+13)
x=y(5x16)=(8x+13)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x16|=|8x+13|
x=+y , +x=y(5x16)=(8x+13)
x=y , x=y(5x16)=(8x+13)

2. Solve the two equations for x

11 additional steps

(5x-16)=(8x+13)

Subtract from both sides:

(5x-16)-8x=(8x+13)-8x

Group like terms:

(5x-8x)-16=(8x+13)-8x

Simplify the arithmetic:

-3x-16=(8x+13)-8x

Group like terms:

-3x-16=(8x-8x)+13

Simplify the arithmetic:

3x16=13

Add to both sides:

(-3x-16)+16=13+16

Simplify the arithmetic:

3x=13+16

Simplify the arithmetic:

3x=29

Divide both sides by :

(-3x)-3=29-3

Cancel out the negatives:

3x3=29-3

Simplify the fraction:

x=29-3

Move the negative sign from the denominator to the numerator:

x=-293

10 additional steps

(5x-16)=-(8x+13)

Expand the parentheses:

(5x-16)=-8x-13

Add to both sides:

(5x-16)+8x=(-8x-13)+8x

Group like terms:

(5x+8x)-16=(-8x-13)+8x

Simplify the arithmetic:

13x-16=(-8x-13)+8x

Group like terms:

13x-16=(-8x+8x)-13

Simplify the arithmetic:

13x16=13

Add to both sides:

(13x-16)+16=-13+16

Simplify the arithmetic:

13x=13+16

Simplify the arithmetic:

13x=3

Divide both sides by :

(13x)13=313

Simplify the fraction:

x=313

3. List the solutions

x=-293,313
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x16|
y=|8x+13|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.