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Solution - Absolute value equations

Exact form: x=3,3
x=3 , 3

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|5x15|+|6x18|=0

Add |6x18| to both sides of the equation:

|5x15|+|6x18||6x18|=|6x18|

Simplify the arithmetic

|5x15|=|6x18|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x15|=|6x18|
without the absolute value bars:

|x|=|y||5x15|=|6x18|
x=+y(5x15)=(6x18)
x=y(5x15)=(6x18)
+x=y(5x15)=(6x18)
x=y(5x15)=(6x18)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x15|=|6x18|
x=+y , +x=y(5x15)=(6x18)
x=y , x=y(5x15)=(6x18)

3. Solve the two equations for x

12 additional steps

(5x-15)=-(6x-18)

Expand the parentheses:

(5x-15)=-6x+18

Add to both sides:

(5x-15)+6x=(-6x+18)+6x

Group like terms:

(5x+6x)-15=(-6x+18)+6x

Simplify the arithmetic:

11x-15=(-6x+18)+6x

Group like terms:

11x-15=(-6x+6x)+18

Simplify the arithmetic:

11x15=18

Add to both sides:

(11x-15)+15=18+15

Simplify the arithmetic:

11x=18+15

Simplify the arithmetic:

11x=33

Divide both sides by :

(11x)11=3311

Simplify the fraction:

x=3311

Find the greatest common factor of the numerator and denominator:

x=(3·11)(1·11)

Factor out and cancel the greatest common factor:

x=3

11 additional steps

(5x-15)=-(-(6x-18))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(5x-15)=6x-18

Subtract from both sides:

(5x-15)-6x=(6x-18)-6x

Group like terms:

(5x-6x)-15=(6x-18)-6x

Simplify the arithmetic:

-x-15=(6x-18)-6x

Group like terms:

-x-15=(6x-6x)-18

Simplify the arithmetic:

x15=18

Add to both sides:

(-x-15)+15=-18+15

Simplify the arithmetic:

x=18+15

Simplify the arithmetic:

x=3

Multiply both sides by :

-x·-1=-3·-1

Remove the one(s):

x=-3·-1

Simplify the arithmetic:

x=3

4. List the solutions

x=3,3
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|5x15|
y=|6x18|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.