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Solution - Absolute value equations

Exact form: x=-132,712
x=-\frac{13}{2} , \frac{7}{12}
Mixed number form: x=-612,712
x=-6\frac{1}{2} , \frac{7}{12}
Decimal form: x=6.5,0.583
x=-6.5 , 0.583

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x10|=|7x+3|
without the absolute value bars:

|x|=|y||5x10|=|7x+3|
x=+y(5x10)=(7x+3)
x=y(5x10)=(7x+3)
+x=y(5x10)=(7x+3)
x=y(5x10)=(7x+3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x10|=|7x+3|
x=+y , +x=y(5x10)=(7x+3)
x=y , x=y(5x10)=(7x+3)

2. Solve the two equations for x

11 additional steps

(5x-10)=(7x+3)

Subtract from both sides:

(5x-10)-7x=(7x+3)-7x

Group like terms:

(5x-7x)-10=(7x+3)-7x

Simplify the arithmetic:

-2x-10=(7x+3)-7x

Group like terms:

-2x-10=(7x-7x)+3

Simplify the arithmetic:

2x10=3

Add to both sides:

(-2x-10)+10=3+10

Simplify the arithmetic:

2x=3+10

Simplify the arithmetic:

2x=13

Divide both sides by :

(-2x)-2=13-2

Cancel out the negatives:

2x2=13-2

Simplify the fraction:

x=13-2

Move the negative sign from the denominator to the numerator:

x=-132

10 additional steps

(5x-10)=-(7x+3)

Expand the parentheses:

(5x-10)=-7x-3

Add to both sides:

(5x-10)+7x=(-7x-3)+7x

Group like terms:

(5x+7x)-10=(-7x-3)+7x

Simplify the arithmetic:

12x-10=(-7x-3)+7x

Group like terms:

12x-10=(-7x+7x)-3

Simplify the arithmetic:

12x10=3

Add to both sides:

(12x-10)+10=-3+10

Simplify the arithmetic:

12x=3+10

Simplify the arithmetic:

12x=7

Divide both sides by :

(12x)12=712

Simplify the fraction:

x=712

3. List the solutions

x=-132,712
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x10|
y=|7x+3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.