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Solution - Absolute value equations

Exact form: x=134,-116
x=\frac{13}{4} , -\frac{11}{6}
Mixed number form: x=314,-156
x=3\frac{1}{4} , -1\frac{5}{6}
Decimal form: x=3.25,1.833
x=3.25 , -1.833

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x1|=|x+12|
without the absolute value bars:

|x|=|y||5x1|=|x+12|
x=+y(5x1)=(x+12)
x=y(5x1)=(x+12)
+x=y(5x1)=(x+12)
x=y(5x1)=(x+12)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x1|=|x+12|
x=+y , +x=y(5x1)=(x+12)
x=y , x=y(5x1)=(x+12)

2. Solve the two equations for x

9 additional steps

(5x-1)=(x+12)

Subtract from both sides:

(5x-1)-x=(x+12)-x

Group like terms:

(5x-x)-1=(x+12)-x

Simplify the arithmetic:

4x-1=(x+12)-x

Group like terms:

4x-1=(x-x)+12

Simplify the arithmetic:

4x1=12

Add to both sides:

(4x-1)+1=12+1

Simplify the arithmetic:

4x=12+1

Simplify the arithmetic:

4x=13

Divide both sides by :

(4x)4=134

Simplify the fraction:

x=134

10 additional steps

(5x-1)=-(x+12)

Expand the parentheses:

(5x-1)=-x-12

Add to both sides:

(5x-1)+x=(-x-12)+x

Group like terms:

(5x+x)-1=(-x-12)+x

Simplify the arithmetic:

6x-1=(-x-12)+x

Group like terms:

6x-1=(-x+x)-12

Simplify the arithmetic:

6x1=12

Add to both sides:

(6x-1)+1=-12+1

Simplify the arithmetic:

6x=12+1

Simplify the arithmetic:

6x=11

Divide both sides by :

(6x)6=-116

Simplify the fraction:

x=-116

3. List the solutions

x=134,-116
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x1|
y=|x+12|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.